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NEW QUESTION: 1
Note: This question is part of a series of questions that present the same scenario. Each question in the series contains a unique solution that might meet the stated goals. Some questions sets might have more than one correct solution, while others might not have a correct solution.
After you answer a question in this section, you will NOT be able to return to it. As a result, these questions will not appear in the review screen.
You have a Microsoft 365 subscription that contains 1,000 user mailboxes.
An administrator named Admin1 must be able to search for the name of a competing company in the mailbox of a user named User5.
You need to ensure that Admin1 can search the mailbox of User5 successfully. The solution must prevent Admin1 from sending email messages as User5.
Solution: You modify the permissions of the mailbox of User5, and then create an eDiscovery case.
Does this meet the goal?
A. Yes
B. No
Answer: B
Explanation:
Explanation
References:
https://docs.microsoft.com/en-us/exchange/policy-and-compliance/ediscovery/ediscovery?view=exchserver-2019

NEW QUESTION: 2
Given the code fragments:
class Employee {
Optional<Address> address;
Employee (Optional<Address> address) {
this.address = address;
}
public Optional<Address> getAddress() { return address; }
}
class Address {
String city = "New York";
public String getCity { return city: }
public String toString() {
return city;
}
}
and
Address address = new Address;
Optional<Address> addrs1 = Optional.ofNullable (address);
Employee e1 = new Employee (addrs1);
String eAddress = (addrs1.isPresent()) ? addrs1.get().getCity() : "City Not available"; System.out.println(eAddress); What is the result?
A. A NoSuchElementException is thrown at run time.
B. City Not available
C. New York
D. null
Answer: D

NEW QUESTION: 3
DRAG DROP
Click and drag the HPE Proliant feature on the left to match it with its description on the right. (Choose all that apply.)

Answer:
Explanation:

NEW QUESTION: 4
Given:
public class Emp {
String fName;
String lName;
public Emp (String fn, String ln) {
fName = fn;
lName = ln;
}
public String getfName() { return fName; }
public String getlName() { return lName; }
}
and the code fragment:
List<Emp> emp = Arrays.asList (
new Emp ("John", "Smith"),
new Emp ("Peter", "Sam"),
new Emp ("Thomas", "Wale"));
emp.stream()
//line n1
.collect(Collectors.toList());
Which code fragment, when inserted at line n1, sorts the employees list in descending order of fName and then ascending order of lName?
A. .map(Emp::getfName).sorted(Comparator.reserveOrder())
B. .sorted
(Comparator.comparing(Emp::getfName).reserved().thenComparing(Emp::getlName))
C. .sorted (Comparator.comparing(Emp::getfName).thenComparing(Emp::getlName))
D. .map(Emp::getfName).sorted(Comparator.reserveOrder().map(Emp::getlName).reserved
Answer: C