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NEW QUESTION: 1
Given: 1. public class TestString3 { 2. public static void main(String[] args) { 3. // insert code here 5. System.out.println(s); 6. } 7. } Which two code fragments, inserted independently at line 3, generate the output 4247? (Choose two.)
A. StringBuffer s = new StringBuffer("123456789");
B. delete(0,3).replace(1,3,"24").delete(4,6);
C. StringBuilder s = new StringBuilder("123456789");
D. substring(3,6).delete(1,2).insert(1, "24");
E. String s = "123456789"; s = (s-"123").replace(1,3,"24") - "89";
F. delete(0,3).delete(1,3).delete(2,5).insert(1, "24");
G. substring(3,6).delete(1,3).insert(1, "24");
H. StringBuilder s = new StringBuilder("123456789");
I. StringBuffer s = new StringBuffer("123456789");
Answer: F,H

NEW QUESTION: 2
Which two settings are configurable as part of a health policy? (Choose two.)
A. advanced malware protection
B. time-synchronization status
C. user access
D. database status
E. intrusion policy preferences
Answer: A,B

NEW QUESTION: 3
Sie erstellen eine Tabelle mit den Spalten StudentCode, SubjectCode und Marks, um die Halbjahresnoten für die Schüler aufzuzeichnen. Die Tabelle enthält Noten von 50 Schülern für verschiedene Fächer.
Sie müssen sicherstellen, dass die obere Hälfte der Schüler, geordnet nach ihren Durchschnittsnoten, den Rang 1 und die übrigen Schüler den Rang 2 erhalten. Welche Transact-SQL-Abfrage sollten Sie verwenden?
A. SELECT StudentCode as Code,
DENSE_RANK () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
B. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANXO OVER (PARTITION BY StudentCode ORDER BY Marks DESC) ALS Rang
FROM StudentMarks) tmp
WO Rang = 1
C. SELECT StudentCode as Code,
NTILE (2) OVER (BESTELLUNG NACH AVG (Marks) DESC) AS-Wert
VON StudentMarks
GROUP BY StudentCode
D. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY StudentCode ORDER BY ASC-Zeichen) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
E. SELECT StudentCode AS Code, Markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION NACH SubjectCode ORDER NACH Marks DESC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
F. SELECT StudentCode AS Code, markiert AS Value FROM (
SELECT StudentCode, Marks AS Marks,
RANK () OVER (PARTITION BY SubjectCode ORDER BY Markiert ASC) AS Rank
FROM StudentMarks) tmp
WO Rang = 1
G. SELECT ID, Name, Markierungen,
DENSE_RANK () ÜBER (ORDER BY Markiert DESC) ALS Rang
VON StudentMarks
H. SELECT StudentCode as Code,
RANG () ÜBER (ORDER BY AVG (Marks) DESC) ALS Wert
VON StudentMarks
GROUP BY StudentCode
Answer: C